advent_of_code/2021/day21_dirac_dice/challenge.txt
2023-05-05 14:42:10 +02:00

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There's not much to do as you slowly descend to the bottom of the ocean. The submarine computer challenges you to a nice game of *Dirac Dice*.
This game consists of a single [die](https://en.wikipedia.org/wiki/Dice), two [pawns](https://en.wikipedia.org/wiki/Glossary_of_board_games#piece), and a game board with a circular track containing ten spaces marked `1` through `10` clockwise. Each player's *starting space* is chosen randomly (your puzzle input). Player 1 goes first.
Players take turns moving. On each player's turn, the player rolls the die *three times* and adds up the results. Then, the player moves their pawn that many times *forward* around the track (that is, moving clockwise on spaces in order of increasing value, wrapping back around to `1` after `10`). So, if a player is on space `7` and they roll `2`, `2`, and `1`, they would move forward 5 times, to spaces `8`, `9`, `10`, `1`, and finally stopping on `2`.
After each player moves, they increase their *score* by the value of the space their pawn stopped on. Players' scores start at `0`. So, if the first player starts on space `7` and rolls a total of `5`, they would stop on space `2` and add `2` to their score (for a total score of `2`). The game immediately ends as a win for any player whose score reaches *at least `1000`*.
Since the first game is a practice game, the submarine opens a compartment labeled *deterministic dice* and a 100-sided die falls out. This die always rolls `1` first, then `2`, then `3`, and so on up to `100`, after which it starts over at `1` again. Play using this die.
For example, given these starting positions:
```
Player 1 starting position: 4
Player 2 starting position: 8
```
This is how the game would go:
* Player 1 rolls `1`+`2`+`3` and moves to space `10` for a total score of `10`.
* Player 2 rolls `4`+`5`+`6` and moves to space `3` for a total score of `3`.
* Player 1 rolls `7`+`8`+`9` and moves to space `4` for a total score of `14`.
* Player 2 rolls `10`+`11`+`12` and moves to space `6` for a total score of `9`.
* Player 1 rolls `13`+`14`+`15` and moves to space `6` for a total score of `20`.
* Player 2 rolls `16`+`17`+`18` and moves to space `7` for a total score of `16`.
* Player 1 rolls `19`+`20`+`21` and moves to space `6` for a total score of `26`.
* Player 2 rolls `22`+`23`+`24` and moves to space `6` for a total score of `22`.
...after many turns...
* Player 2 rolls `82`+`83`+`84` and moves to space `6` for a total score of `742`.
* Player 1 rolls `85`+`86`+`87` and moves to space `4` for a total score of `990`.
* Player 2 rolls `88`+`89`+`90` and moves to space `3` for a total score of `745`.
* Player 1 rolls `91`+`92`+`93` and moves to space `10` for a final score, `1000`.
Since player 1 has at least `1000` points, player 1 wins and the game ends. At this point, the losing player had `745` points and the die had been rolled a total of `993` times; `745 * 993 = *739785*`.
Play a practice game using the deterministic 100-sided die. The moment either player wins, *what do you get if you multiply the score of the losing player by the number of times the die was rolled during the game?*
Your puzzle answer was `518418`.
\--- Part Two ---
----------
Now that you're warmed up, it's time to play the real game.
A second compartment opens, this time labeled *Dirac dice*. Out of it falls a single three-sided die.
As you experiment with the die, you feel a little strange. An informational brochure in the compartment explains that this is a *quantum die*: when you roll it, the universe *splits into multiple copies*, one copy for each possible outcome of the die. In this case, rolling the die always splits the universe into *three copies*: one where the outcome of the roll was `1`, one where it was `2`, and one where it was `3`.
The game is played the same as before, although to prevent things from getting too far out of hand, the game now ends when either player's score reaches at least `*21*`.
Using the same starting positions as in the example above, player 1 wins in `*444356092776315*` universes, while player 2 merely wins in `341960390180808` universes.
Using your given starting positions, determine every possible outcome. *Find the player that wins in more universes; in how many universes does that player win?*
Your puzzle answer was `116741133558209`.
Both parts of this puzzle are complete! They provide two gold stars: \*\*
At this point, you should [return to your Advent calendar](/2021) and try another puzzle.
If you still want to see it, you can [get your puzzle input](21/input).