Added Solution for 2021 day 06

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Burnus 2023-04-19 21:02:05 +02:00
parent 4da49bde8d
commit 65859a6142
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[package]
name = "day06_lanternfish"
version = "0.1.0"
edition = "2021"
# See more keys and their definitions at https://doc.rust-lang.org/cargo/reference/manifest.html
[dependencies]

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The sea floor is getting steeper. Maybe the sleigh keys got carried this way?
A massive school of glowing [lanternfish](https://en.wikipedia.org/wiki/Lanternfish) swims past. They must spawn quickly to reach such large numbers - maybe *exponentially* quickly? You should model their growth rate to be sure.
Although you know nothing about this specific species of lanternfish, you make some guesses about their attributes. Surely, each lanternfish creates a new lanternfish once every *7* days.
However, this process isn't necessarily synchronized between every lanternfish - one lanternfish might have 2 days left until it creates another lanternfish, while another might have 4. So, you can model each fish as a single number that represents *the number of days until it creates a new lanternfish*.
Furthermore, you reason, a *new* lanternfish would surely need slightly longer before it's capable of producing more lanternfish: two more days for its first cycle.
So, suppose you have a lanternfish with an internal timer value of `3`:
* After one day, its internal timer would become `2`.
* After another day, its internal timer would become `1`.
* After another day, its internal timer would become `0`.
* After another day, its internal timer would reset to `6`, and it would create a *new* lanternfish with an internal timer of `8`.
* After another day, the first lanternfish would have an internal timer of `5`, and the second lanternfish would have an internal timer of `7`.
A lanternfish that creates a new fish resets its timer to `6`, *not `7`* (because `0` is included as a valid timer value). The new lanternfish starts with an internal timer of `8` and does not start counting down until the next day.
Realizing what you're trying to do, the submarine automatically produces a list of the ages of several hundred nearby lanternfish (your puzzle input). For example, suppose you were given the following list:
```
3,4,3,1,2
```
This list means that the first fish has an internal timer of `3`, the second fish has an internal timer of `4`, and so on until the fifth fish, which has an internal timer of `2`. Simulating these fish over several days would proceed as follows:
```
Initial state: 3,4,3,1,2
After 1 day: 2,3,2,0,1
After 2 days: 1,2,1,6,0,8
After 3 days: 0,1,0,5,6,7,8
After 4 days: 6,0,6,4,5,6,7,8,8
After 5 days: 5,6,5,3,4,5,6,7,7,8
After 6 days: 4,5,4,2,3,4,5,6,6,7
After 7 days: 3,4,3,1,2,3,4,5,5,6
After 8 days: 2,3,2,0,1,2,3,4,4,5
After 9 days: 1,2,1,6,0,1,2,3,3,4,8
After 10 days: 0,1,0,5,6,0,1,2,2,3,7,8
After 11 days: 6,0,6,4,5,6,0,1,1,2,6,7,8,8,8
After 12 days: 5,6,5,3,4,5,6,0,0,1,5,6,7,7,7,8,8
After 13 days: 4,5,4,2,3,4,5,6,6,0,4,5,6,6,6,7,7,8,8
After 14 days: 3,4,3,1,2,3,4,5,5,6,3,4,5,5,5,6,6,7,7,8
After 15 days: 2,3,2,0,1,2,3,4,4,5,2,3,4,4,4,5,5,6,6,7
After 16 days: 1,2,1,6,0,1,2,3,3,4,1,2,3,3,3,4,4,5,5,6,8
After 17 days: 0,1,0,5,6,0,1,2,2,3,0,1,2,2,2,3,3,4,4,5,7,8
After 18 days: 6,0,6,4,5,6,0,1,1,2,6,0,1,1,1,2,2,3,3,4,6,7,8,8,8,8
```
Each day, a `0` becomes a `6` and adds a new `8` to the end of the list, while each other number decreases by 1 if it was present at the start of the day.
In this example, after 18 days, there are a total of `26` fish. After 80 days, there would be a total of `*5934*`.
Find a way to simulate lanternfish. *How many lanternfish would there be after 80 days?*
Your puzzle answer was `366057`.
\--- Part Two ---
----------
Suppose the lanternfish live forever and have unlimited food and space. Would they take over the entire ocean?
After 256 days in the example above, there would be a total of `*26984457539*` lanternfish!
*How many lanternfish would there be after 256 days?*
Your puzzle answer was `1653559299811`.
Both parts of this puzzle are complete! They provide two gold stars: \*\*
At this point, you should [return to your Advent calendar](/2021) and try another puzzle.
If you still want to see it, you can [get your puzzle input](6/input).

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use std::num::ParseIntError;
pub fn run(input: &str) -> Result<(usize, usize), ParseIntError> {
let fish: Vec<_> = input.split(',').map(|i| i.parse::<u8>()).collect::<Result<Vec<_>, _>>()?;
let mut ages: Vec<usize> = (0..=8).map(|age| fish.iter().filter(|fish_age| **fish_age == age).count()).collect();
for _ in 0..80 {
let new = ages[0];
(0..8).for_each(|age| ages[age] = ages[age+1]);
ages[6] += new;
ages[8] = new;
}
let first = ages.iter().sum();
for _ in 80..256 {
let new = ages[0];
(0..8).for_each(|age| ages[age] = ages[age+1]);
ages[6] += new;
ages[8] = new;
}
let second = ages.iter().sum();
Ok((first, second))
}
#[cfg(test)]
mod tests {
use super::*;
use std::fs::read_to_string;
fn read_file(name: &str) -> String {
read_to_string(name).expect(&format!("Unable to read file: {name}")[..]).trim().to_string()
}
#[test]
fn test_sample() {
let sample_input = read_file("tests/sample_input");
assert_eq!(run(&sample_input), Ok((5934, 26984457539)));
}
#[test]
fn test_challenge() {
let challenge_input = read_file("tests/challenge_input");
assert_eq!(run(&challenge_input), Ok((366057, 1653559299811)));
}
}

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1,2,1,3,2,1,1,5,1,4,1,2,1,4,3,3,5,1,1,3,5,3,4,5,5,4,3,1,1,4,3,1,5,2,5,2,4,1,1,1,1,1,1,1,4,1,4,4,4,1,4,4,1,4,2,1,1,1,1,3,5,4,3,3,5,4,1,3,1,1,2,1,1,1,4,1,2,5,2,3,1,1,1,2,1,5,1,1,1,4,4,4,1,5,1,2,3,2,2,2,1,1,4,3,1,4,4,2,1,1,5,1,1,1,3,1,2,1,1,1,1,4,5,5,2,3,4,2,1,1,1,2,1,1,5,5,3,5,4,3,1,3,1,1,5,1,1,4,2,1,3,1,1,4,3,1,5,1,1,3,4,2,2,1,1,2,1,1,2,1,3,2,3,1,4,5,1,1,4,3,3,1,1,2,2,1,5,2,1,3,4,5,4,5,5,4,3,1,5,1,1,1,4,4,3,2,5,2,1,4,3,5,1,3,5,1,3,3,1,1,1,2,5,3,1,1,3,1,1,1,2,1,5,1,5,1,3,1,1,5,4,3,3,2,2,1,1,3,4,1,1,1,1,4,1,3,1,5,1,1,3,1,1,1,1,2,2,4,4,4,1,2,5,5,2,2,4,1,1,4,2,1,1,5,1,5,3,5,4,5,3,1,1,1,2,3,1,2,1,1

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3,4,3,1,2